5y(3-y)(4y+1)^2=0

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Solution for 5y(3-y)(4y+1)^2=0 equation: 



5y(3-y)(4y+1)^2=0

We add all the numbers together, and all the variables

5y(-1y+3)(4y+1)^2=0

We multiply parentheses ..

5y(-4y^2-1y+12y+3)^2=0

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